Ball spots can roughly be the equivalent of games spots in 9 ball. The FargoRate site provides tools to get percentages. For example, if 9-8 is a fair match, FargoRate tells you that the two players are 17.6 FargoRate points apart. If you then set the match to 8-8, you get the match odds of 59% for the better player. I think this doesn't work so accurately for top-end players who can run 8-and-out, but it is a start.For example, if I gave someone 8-7 but instead of balls they would rather get odds on the money. What would that equate too? How about other spots as well?
8-7 =
8-6 =
9-7=
and so on
Maybe I did the numbers wrong. It does seem a little lopsided.that cant be right. 9,8 difference changing one ball certainly isnt 59% then you would be saying laying 3 to 2 in the money is about fair. thats crazy.
Well, if you trust the FargoRate math, if 10-6 is a draw, 8-8 is going to favor the stronger player 85%-15% or about 6:1 on the money. I imagine a lot of players would take 2:1 on the money instead of 10-6. They might figure that since the ratio is better, it must be a better game. They might really go for 3:1.also with bigger spots it gets even better for the better player
Lets say you give a guy 10 6 and instead play even. How many games will that guy win in 20
to make it close to fair it would have t be like 10 to 1 on the money I would say and if the better player is careful they should still come out ahead
Obviously not giving +150 to a guy I give 9/8 to. Maybe +110
I'd like to see what you came up with Bob. This whole question is an interesting topic.Ball spots can roughly be the equivalent of games spots in 9 ball. The FargoRate site provides tools to get percentages. For example, if 9-8 is a fair match, FargoRate tells you that the two players are 17.6 FargoRate points apart. If you then set the match to 8-8, you get the match odds of 59% for the better player. I think this doesn't work so accurately for top-end players who can run 8-and-out, but it is a start.
A table of FargoRate equivalences to one pocket spots is in my November 2019 column in Billiards Digest.
I don't think thats right. I play a few guys that give me 10-6 and i would mortgage my house to play 8-8 if I was getting 10 to1 on the money!!! Kalso with bigger spots it gets even better for the better player
Lets say you give a guy 10 6 and instead play even. How many games will that guy win in 20
to make it close to fair it would have t be like 10 to 1 on the money I would say and if the better player is careful they should still come out ahead
And so if the roles were reversed you would take 11-10 on the money to play even?Obviously not giving +150 to a guy I give 9/8 to. Maybe +110
Maybe I lent to the confusion. The FargoRate tool doesn't much care whether it's counting nine-ball games or balls made within a single game of one pocket. The underlying math is the same. On the FargoRate site it is stated as games, but we can use it as balls.seems we are confusing a race to game by game which i think was the original post.
And so if the roles were reversed you would take 11-10 on the money to play even?
So, yu don't think you can win 6 out of ten games playing him even? Of course you can, probably more than that. Well if you are giving 3 to 2 on the money and he's betting $100, you are betting $150 and you win 6 out of 10 games, you just broke even on the money. That is not fair to you?
Sounds as though maybe you are looking to rob this poor bastard.
He has to win just as many games as you do to win any money at all. Why would he take that bet if you have been giving him 9/8?
So, yu don't think you can win 6 out of ten games playing him even? Of course you can, probably more than that. Well if you are giving 3 to 2 on the money and he's betting $100, you are betting $150 and you win 6 out of 10 games, you just broke even on the money. That is not fair to you?
Sounds as though maybe you are looking to rob this poor bastard.
He has to win just as many games as you do to win any money at all. Why would he take that bet if you have been giving him 9/8?