Artie Bodendorfer
Verified Member
- Joined
- Nov 18, 2005
- Messages
- 4,271
wincardona said:If player A is entitled to 10/7 from player B and player C spots player B 10/7 I feel that a fair game between player A playing player C would be something close to 12/6 or 11/5. Possibly 11/5 on his break and 12/6 on player A's break. I believe that that would be a good spot to start with.
I figured that by adding 1 to 2 balls onto player C's total and deducting 1 to 2 ball from player A's total would be the fairest thing to do. It would be unfair to player A if 3 balls would be added to player C's total= 13/7, or 3 balls deducted from player A's total=10/4. So a somewhat compromise is possibly what we should be looking for, adjusting the spot to one game 12/6 and one game 11/5.
Billy I.
A fair game would be 11 to 5 and breack apeace if thats howe they are playing.
THe 12 to 6 is way out off line and it would be a stch up. Player C would have no chance beating player B at that game. 11 to 5 both games would be close.
This is another qouistion for a probability expert to figure out. And he could breack it down too the exacte percentage.
If someone has a probability expert have him do the math and he will come out with the exacte percentage.
I do not nohowe too do that. Or I could give you the exact percentage. For the game.
But they can come up with the correct answer.